In triangle $$ABC$$, $$AB=\sqrt{30}$$, $$AC=\sqrt{6}$$, and $$BC=\sqrt{15}$$. There is a point $$D$$ for which $$\overline{AD}$$ bisects $$\overline{BC}$$, and $$\angle ADB$$ is a right angle. The ratio $\frac{\text{Area}(\triangle ADB)}{\text{Area}(\triangle ABC)}$ can be written in the form $$\frac{m}{n}$$, where $$m$$ and $$n$$ are relatively prime positive integers. Find $$m+n$$.

(第十四届AIME1996 第13题)